Schaum's 3000 Solved Problems in Physics · Problem 4.9 · Newton's laws

Trunk sliding to a stop

The trunk moves one way. The force points the other. Both are true at once.

A 40-kg trunk sliding across a floor slows down from 5.0 to 2.0 m/s in 6.0 s. Assuming that the force acting on the trunk is constant, find its magnitude and its direction relative to the velocity vector of the trunk.as printed, page 52

Tap any symbol, here or in a formula, to see what it is and its value.

The picture
40 kg v = 5.0 m/s F = 20 N, backward
time0.0 s
speed5.0 m/s
distance0.0 m
5 m/s2 m/s0 6.0 s slope = (2 − 5) ÷ 6 = −0.5 m/s² · the force is the slope times the mass
Feel the numbers
20 Nthe force

Two kilograms' worth of weight, dragging sideways on a forty-kilogram trunk. A very slippery floor.

0.05 g0.5 m/s²

You would barely feel this in a car. It takes the trunk twenty seconds to slide to a full stop from 5 m/s.

21 mdistance in the six seconds

Not asked, but the average speed was 3.5 m/s for six seconds. A long slide.

The walkthrough

Press play and it reads straight through, scrolling as it goes. Space pauses. ← → move a step. ▶ on a step plays from there.

Every symbol
Narrated by the Listen voice. Timing comes from the narration itself, so the light lands on the part of the formula that is being said.
epicnotes